The length,breadth,and thickness of a rectang | vedclass

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Question

(D) Length of sheet,$l = 4.234 \; m$ ($4$ significant figures).Breadth of sheet,$b = 1.005 \; m$ ($4$ significant figures).Thickness of sheet,$h = 2.0

Vedclass · Accepted Answer

$8.72 \; m^2$ and $0.0855 \; m^3$

Vedclass · Answer

(D) Length of sheet,$l = 4.234 \; m$ ($4$ significant figures).Breadth of sheet,$b = 1.005 \; m$ ($4$ significant figures).Thickness of sheet,$h = 2.01 \; cm = 0.0201 \; m$ ($3$ significant figures).The result of multiplication or division must have the same number of significant figures as the measurement with the least significant figures. Here,the least number of significant figures is $3$.Surface area of the sheet $= 2(l 	imes b + b 	imes h + h 	imes l)$$= 2(4.234 	imes 1.005 + 1.005 	imes 0.0201 + 0.0201 	imes 4.234)$$= 2(4.25517 + 0.02020 + 0.08510)$$= 2(4.36047) = 8.72094 \; m^2$.Rounding to $3$ significant figures,we get $8.72 \; m^2$.Volume of the sheet $= l 	imes b 	imes h$$= 4.234 	imes 1.005 	imes 0.0201 = 0.085553 \; m^3$.Rounding to $3$ significant figures,we get $0.0856 \; m^3$ (Note: The provided option $D$ uses $0.0855$,but $0.0856$ is the correct rounding of $0.085553$. Given the options,$D$ is the closest intended answer).

The length,breadth,and thickness of a rectangular sheet of metal are $4.234 \; m$,$1.005 \; m$,and $2.01 \; cm$ respectively. Give the area and volume of the sheet to correct significant figures.

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