The length and breadth of a rectangular piece of land are in the ratio $5:3$. The owner spent ₹ $6000$ for fencing it from all sides at the rate of ₹ $7.50$ per metre. The difference between its length and breadth is (in metres):

$3$ horses are tethered at $3$ corners of a triangular plot of land having sides $20 \, m$,$30 \, m$,and $40 \, m$,each with a rope of length $7 \, m$. The area (in $m^2$) of the region of this plot,which can be grazed by the horses,is (Use $\pi = \frac{22}{7}$)

In $\Delta ABC$,$AD$ and $AE$ are bisectors of $\angle BAC$ and $\angle BAD$ respectively. If $\angle BAE = 30^{\circ}$,$AE = 9 \text{ cm}$,and $EC = 15 \text{ cm}$,what is the area (in $\text{cm}^2$) of $\Delta AEC$?

$ABCD$ is a trapezium with $AD$ and $BC$ as parallel sides. $E$ is a point on $BC$. The ratio of the area of $ABCD$ to that of $\Delta AED$ is

$A$ plot of land is in the shape of a right-angled isosceles triangle. The length of the hypotenuse is $50 \sqrt{2} \text{ m}$. The cost of fencing is ₹$3$ per metre. The total cost of fencing the plot will be

$A$ rectangular field costs $Rs. 110$ for levelling at $50$ $paise$ per square metre. If the ratio of length to breadth is $11: 5$, find the length of the field (in $m$).