The length of a diagonal of a square is 8 sqr | vedclass

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(B) Let the side of the square be $a$.We know that the length of the diagonal of a square is given by the formula $d = a \sqrt{2}$.Given that the diag

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$32$

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(B) Let the side of the square be $a$.We know that the length of the diagonal of a square is given by the formula $d = a \sqrt{2}$.Given that the diagonal $d = 8 \sqrt{2}$.Equating the two,we get $a \sqrt{2} = 8 \sqrt{2}$.Dividing both sides by $\sqrt{2}$,we find the side length $a = 8$.The perimeter of a square is given by the formula $P = 4 	imes a$.Substituting the value of $a$,we get $P = 4 	imes 8 = 32$.

The length of a diagonal of a square is $8 \sqrt{2}$. Then,the perimeter of the square is..............

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