The length of an open organ pipe is twice the | vedclass

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(C) Let the length of the open organ pipe be $L_o$ and the length of the closed organ pipe be $L_c$.Given that $L_o = 2 L_c$.The fundamental frequency

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$300$

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(C) Let the length of the open organ pipe be $L_o$ and the length of the closed organ pipe be $L_c$.Given that $L_o = 2 L_c$.The fundamental frequency of an open organ pipe is given by $f_o = \frac{v}{2 L_o} = 100 \ Hz$.From this,we get $\frac{v}{L_o} = 200 \ Hz$.Substituting $L_o = 2 L_c$,we get $\frac{v}{2 L_c} = 200 \ Hz$,which implies $\frac{v}{L_c} = 400 \ Hz$.The fundamental frequency of a closed organ pipe is $f_c = \frac{v}{4 L_c} = \frac{400}{4} = 100 \ Hz$.The harmonics of a closed organ pipe are odd multiples of the fundamental frequency $(f_c, 3f_c, 5f_c, \dots)$.The third harmonic of the closed pipe is $3 f_c = 3 	imes 100 = 300 \ Hz$.

The length of an open organ pipe is twice the length of another closed organ pipe. The fundamental frequency of the open pipe is $100 \ Hz$. The frequency of the third harmonic of the closed pipe is ..... $Hz$.

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