The length of canvas 75 , cm wide required to | vedclass

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(A) Given: Height of the cone $h = 14 \, m$,Floor area $= \pi r^{2} = 346.5 \, m^{2}$.First,find the radius $r$:$\frac{22}{7} 	imes r^{2} = 346.5$$r^

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$770$

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(A) Given: Height of the cone $h = 14 \, m$,Floor area $= \pi r^{2} = 346.5 \, m^{2}$.First,find the radius $r$:$\frac{22}{7} 	imes r^{2} = 346.5$$r^{2} = \frac{346.5 	imes 7}{22} = 110.25$$r = \sqrt{110.25} = 10.5 \, m$.Now,find the slant height $l$:$l = \sqrt{r^{2} + h^{2}} = \sqrt{10.5^{2} + 14^{2}} = \sqrt{110.25 + 196} = \sqrt{306.25} = 17.5 \, m$.Curved surface area of the tent $= \pi r l = \frac{22}{7} 	imes 10.5 	imes 17.5 = 22 	imes 1.5 	imes 17.5 = 577.5 \, m^{2}$.Width of canvas $= 75 \, cm = 0.75 \, m$.Length of canvas $= \frac{	ext{Curved surface area}}{	ext{Width}} = \frac{577.5}{0.75} = 770 \, m$.

The length of canvas $75 \, cm$ wide required to build a conical tent of height $14 \, m$ and the floor area $346.5 \, m^{2}$ is.........$m$

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