The length of the simple pendulum is made 3 t | vedclass

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(B) The time period $T$ of a simple pendulum is given by the formula: $T = 2\pi \sqrt{\frac{L}{g}}$,where $L$ is the length of the pendulum and $g$ is

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$\sqrt{3} T$

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(B) The time period $T$ of a simple pendulum is given by the formula: $T = 2\pi \sqrt{\frac{L}{g}}$,where $L$ is the length of the pendulum and $g$ is the acceleration due to gravity.From this formula,we can see that $T \propto \sqrt{L}$.Let the original length be $L_1 = L$ and the original time period be $T_1 = T$.The new length is $L_2 = 3L$.Let the new time period be $T_2$.Using the proportionality $T \propto \sqrt{L}$,we have: $\frac{T_2}{T_1} = \sqrt{\frac{L_2}{L_1}}$.Substituting the values: $\frac{T_2}{T} = \sqrt{\frac{3L}{L}} = \sqrt{3}$.Therefore,$T_2 = \sqrt{3} T$.

The length of the simple pendulum is made $3$ times the original length. If $T$ is its original time period,then the new time period will be:

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