The light of wavelength $6328 \ \mathring{A}$ is incident on a slit of width $0.2 \ mm$ perpendicularly. The angular width of the central maxima will be.....$^o$

In a Fraunhofer diffraction experiment, a single slit of width $0.5 ~mm$ is illuminated by a monochromatic light of wavelength $600 ~nm$. The diffraction pattern is observed on a screen at a distance of $50 ~cm$ from the slit. What will be the linear separation of the first order minima (in $~mm$)?

In a single slit diffraction pattern,the distance between the plane of the slit and the screen is $1.3 \ m$. The width of the slit is $0.65 \ mm$ and the second maximum is formed at a distance of $2.6 \ mm$ from the center of the screen. The wavelength of light used is: (in $Å$)

If a classroom door is open just a small amount, we can hear sounds coming from the room but we can't see what is going on inside the room because

$A$ Fraunhofer diffraction pattern due to a single slit of width $0.3 \text{ mm}$ is obtained on a screen placed at a distance of $3 \text{ m}$ from the slit. The first minima lie at $5.5 \text{ mm}$ on either side of the central maximum on the screen. The wavelength of light used is (in $\text{ Å}$)

$A$ plane wave front of wavelength $\lambda$ is incident on a single slit of width $b$. What is the angular width of the secondary maximum?