(D) First,find the slope $m$ of the line passing through $(-1, 3)$ and $(4, -2)$:$m = \frac{-2 - 3}{4 - (-1)} = \frac{-5}{5} = -1$Using the point-slop

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(D) First,find the slope $m$ of the line passing through $(-1, 3)$ and $(4, -2)$:$m = \frac{-2 - 3}{4 - (-1)} = \frac{-5}{5} = -1$Using the point-slope form $(y - y_1) = m(x - x_1)$ with point $(-1, 3)$:$y - 3 = -1(x - (-1))$$y - 3 = -1(x + 1)$$y - 3 = -x - 1$$x + y = 2$If the line passes through the point $(p, q)$,then the coordinates must satisfy the equation:$p + q = 2$

Class 11 Mathematics Straight Lines Slope of line, Equation of line in different forms

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The line joining the points $(-1, 3)$ and $(4, -2)$ will pass through the point $(p, q)$ if

A
$p - q = 1$
B
$p + q = 1$
C
$p - q = 2$
D
$p + q = 2$

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Class 11 Questions

Class 11

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Straight Lines

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Slope of line, Equation of line in different forms

Find the value of $k$ for which the line $(k-3) x - (4-k^2) y + k^2 - 7k + 6 = 0$ passes through the origin.

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The equation of the line parallel to $x/a + y/b = 1$ and passing through $(a, b)$ is .....

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The line joining the points $(-1, 3)$ and $(4, -2)$ will pass through the point $(p, q)$ if

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Find the value of $k$ for which the line $(k-3) x - (4-k^2) y + k^2 - 7k + 6 = 0$ passes through the origin.

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