The linkage map of $X$-chromosome of fruit fly has $66$ units with yellow body gene $(y)$ at one end and bobbed hair $(b)$ gene at the other end. The recombination frequency between these two genes ($y$ and $b$) should be

  • A
    $100\%$
  • B
    $66\%$
  • C
    $> 50\%$
  • D
    $5.50\%$

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