The logic circuit shown below has the input w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given circuit consists of two $NOT$ gates followed by a $NOR$ gate.Let the inputs be $A$ and $B$. The outputs of the $NOT$ gates are $\bar{A}$

Vedclass · Accepted Answer

Vedclass · Answer

(A) The given circuit consists of two $NOT$ gates followed by a $NOR$ gate.Let the inputs be $A$ and $B$. The outputs of the $NOT$ gates are $\bar{A}$ and $\bar{B}$.These are fed into a $NOR$ gate, so the final output $Y$ is:$Y = \overline{\bar{A} + \bar{B}}$Using De Morgan's theorem, $\overline{\bar{A} + \bar{B}} = \overline{\bar{A}} \cdot \overline{\bar{B}} = A \cdot B$.Thus, the circuit acts as an $AND$ gate.The truth table for an $AND$ gate is:$A$$B$$Y$$0$$0$$0$$0$$1$$0$$1$$0$$0$$1$$1$$1$Comparing the input waveforms $A$ and $B$ with the $AND$ gate logic, the output $Y$ is high $(1)$ only when both $A$ and $B$ are high $(1)$. Looking at the provided waveforms, this corresponds to option $A$.

The logic circuit shown below has the input waveforms $A$ and $B$ as shown. Pick out the correct output waveform.

Similar Questions

The truth table for the following logic circuit is:

Find the truth table for the function $Y$ with inputs $A$ and $B$ represented in the following figure.

If $ A=1 $ and $ B=0 $,then in terms of Boolean algebra,$ \bar{A}+B= $

$A$ typical integrated circuit $(IC)$ consisting of logic gates $\leq 1000$ is termed as

Consider the logic circuit with inputs $A, B, C$ and output $Y$. How many combinations of $A, B$ and $C$ give the output $Y=0$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module