The Lorentz magnetic force is acting on a particle of charge $q$ moving with velocity $\vec{v}$ in a magnetic field $\vec{B}$. The work done by this force on the charged particle is

What is the behavior of a charged particle moving in a region where the electric field $\vec{E}$ and magnetic field $\vec{B}$ are perpendicular to each other?

$A$ particle having charge $10^{-9} \text{ C}$ moving in the $x-y$ plane in fields of $0.4 \hat{i} \text{ N/C}$ and $4 \times 10^{-3} \hat{k} \text{ T}$ experiences a force of $(4 \hat{i} + 2 \hat{j}) \times 10^{-10} \text{ N}$. The velocity of the particle at that instant is . . . . . . $\text{m/s}$.

The dimension of the magnetic field in terms of $M, L, T$ and $C$ (coulomb) is given as:

$A$ charged particle carrying charge $1\,\mu C$ is moving with velocity $(2 \hat{i} + 3 \hat{j} + 4 \hat{k})\, ms^{-1}$. If an external magnetic field of $(5 \hat{i} + 3 \hat{j} - 6 \hat{k}) \times 10^{-3}\, T$ exists in the region where the particle is moving,then the force on the particle is $\overrightarrow{F} \times 10^{-9}\, N$. The vector $\overrightarrow{F}$ is:

$A$ particle of charge $q$ and velocity $v$ passes undeflected through a space with non-zero electric field $E$ and magnetic field $B$. The undeflected condition will hold if: