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(A) For a long straight cylindrical conductor of radius $a$ carrying a steady current $I$ uniformly distributed over its cross-section:$1$. Inside the

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(A) For a long straight cylindrical conductor of radius $a$ carrying a steady current $I$ uniformly distributed over its cross-section:$1$. Inside the conductor $(r $2$. Outside the conductor $(r > a)$: The magnetic field $B$ is given by $B = \frac{\mu_0 I}{2 \pi r}$. This shows that $B \propto \frac{1}{r}$,which is a hyperbolic relationship.$3$. At the surface $(r = a)$: The magnetic field is maximum,$B_{max} = \frac{\mu_0 I}{2 \pi a}$.Comparing these characteristics with the given graphs,the graph in option $A$ correctly shows a linear increase for $r  a$.

The magnetic field due to a straight conductor of uniform cross section of radius $a$ and carrying a steady current is represented by

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