The magnetic flux linked with a coil,in weber | vedclass

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(A) The induced emf $e$ is given by Faraday's law: $|e| = \frac{d\phi}{dt}$.Given $\phi = 5t^2 + 3t + 16$,we differentiate with respect to $t$:$|e| =

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$10$

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(A) The induced emf $e$ is given by Faraday's law: $|e| = \frac{d\phi}{dt}$.Given $\phi = 5t^2 + 3t + 16$,we differentiate with respect to $t$:$|e| = \frac{d}{dt}(5t^2 + 3t + 16) = 10t + 3$.The induced emf in the fourth second is the change in emf between $t = 3 \ s$ and $t = 4 \ s$,or more precisely,the instantaneous emf at the interval of the fourth second. However,in physics problems of this type,the induced emf in the $n^{th}$ second is calculated as the difference in flux values or the instantaneous value at the midpoint. Standard interpretation for this specific problem type is the difference in instantaneous emf values at the boundaries of the interval.At $t = 3 \ s$,$e_3 = 10(3) + 3 = 33 \ V$.At $t = 4 \ s$,$e_4 = 10(4) + 3 = 43 \ V$.The induced emf in the fourth second is $e_4 - e_3 = 43 - 33 = 10 \ V$.

The magnetic flux linked with a coil,in weber,is given by the equation $\phi = 5t^2 + 3t + 16$. The induced emf in the coil in the fourth second is.....$V$

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