The magnetic moment of [CoF_6]^{3-} as per sp | vedclass

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(D) In the complex $[CoF_6]^{3-}$,the oxidation state of $Co$ is $x + 6(-1) = -3$,which gives $x = +3$.The electronic configuration of $Co^{3+}$ is $[

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$4.9$

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(D) In the complex $[CoF_6]^{3-}$,the oxidation state of $Co$ is $x + 6(-1) = -3$,which gives $x = +3$.The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since $F^-$ is a weak field ligand,it does not cause pairing of electrons.Thus,the $3d$ orbitals have $4$ unpaired electrons $(n = 4)$.The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$.Substituting $n = 4$,we get $\mu = \sqrt{4(4+2)} = \sqrt{24} \approx 4.90 \ BM$.

The magnetic moment of $[CoF_6]^{3-}$ as per spin only formula (in $BM$) is

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