The magnetic moment of a magnet of length $10\, cm$ and pole strength $4.0\, Am$ will be......$A\,m^2$.

$A$ bar magnet having centre $O$ has a length of $4 \ cm$. Point $P_1$ is in the broad side-on (equatorial) position and $P_2$ is in the end side-on (axial) position with $OP_1 = OP_2 = 10 \ m$. The ratio of magnetic intensities $H$ at $P_1$ and $P_2$ is:

Write the analogy between electrostatics and magnetism.

$A$ sample of a ferromagnetic iron in the shape of a cube of side $1.0 \mu m$ contains $8.7 \times 10^{28}$ atoms per cubic metre and the magnetic dipole moment of each iron atom is $9.3 \times 10^{-24} A m^2$. Then the maximum possible magnetic dipole moment (in $A m^2$) of the sample is nearly

$A$ cylindrical rod magnet has a length of $5 \, cm$ and a diameter of $1 \, cm$. It has a uniform magnetization of $5.30 \times 10^3 \, A/m$. What is its magnetic dipole moment?

The magnetic moment of an atomic neon is