The magnetic moment of the complex [Ni(NH_3)_ | vedclass

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(B) $1$. In the complex $[Ni(NH_3)_6]Cl_2$,the oxidation state of $Ni$ is $+2$. $2$. The atomic number of $Ni$ is $28$,so its electronic configuration

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$\sqrt{8} \ BM$

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(B) $1$. In the complex $[Ni(NH_3)_6]Cl_2$,the oxidation state of $Ni$ is $+2$. $2$. The atomic number of $Ni$ is $28$,so its electronic configuration is $[Ar] 3d^8 4s^2$. $3$. For $Ni^{2+}$,the configuration is $[Ar] 3d^8$. $4$. $NH_3$ is a ligand,but in an octahedral field with $d^8$ configuration,the electrons are arranged as $t_{2g}^6 e_g^2$. $5$. There are $2$ unpaired electrons in the $3d$ orbitals. $6$. The magnetic moment $\mu$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. $7$. Substituting $n = 2$,we get $\mu = \sqrt{2(2+2)} = \sqrt{8} \ BM$.

List-$I$ (Complex)	List-$II$ (Spin only Magnetic moment)
$A$. $[CoF_6]^{3-}$	$I$. $0$
$B$. $[Co(C_2O_4)_3]^{3-}$	$II$. $\sqrt{24}$
$C$. $[FeF_6]^{3-}$	$III$. $\sqrt{8}$
$D$. $[Mn(CN)_6]^{3-}$	$IV$. $\sqrt{35}$
	$V$. $\sqrt{15}$

The magnetic moment of the complex $[Ni(NH_3)_6]Cl_2$ is

Similar Questions

Match the following:

List-$I$ (Complex) List-$II$ (Spin only Magnetic moment)

$A$. $[CoF_6]^{3-}$ $I$. $0$

$B$. $[Co(C_2O_4)_3]^{3-}$ $II$. $\sqrt{24}$

$C$. $[FeF_6]^{3-}$ $III$. $\sqrt{8}$

$D$. $[Mn(CN)_6]^{3-}$ $IV$. $\sqrt{35}$

$V$. $\sqrt{15}$

The number of geometrical isomers of $[CrCl_2(en)(NH_3)_2]$,where $en = \text{ethylenediamine}$,is

Among $(i)$ $[Cr(en)_{3}]^{3+}$,$(ii)$ $trans-[Cr(en)_{2}Cl_{2}]^{+}$,$(iii)$ $cis-[Cr(en)_{2}Cl_{2}]^{+}$,$(iv)$ $[Co(NH_{3})_{4}Cl_{2}]^{+}$,the optically active complexes are:

The theoretical value of the magnetic moment of the complex ion $[Ni(Cl)_4]^{2-}$ is .......... $B.M.$

What are the number of possible geometric isomers,optical isomers,and total isomers for the complex $[CoCl_2(en)(NH_3)_2]^{+}$ respectively?

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