The magnetic susceptibility of a paramagnetic | vedclass

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(C) According to Curie's law for a paramagnetic substance,the magnetic susceptibility $\chi_m$ is inversely proportional to the absolute temperature $

Vedclass · Accepted Answer

$-73$

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(C) According to Curie's law for a paramagnetic substance,the magnetic susceptibility $\chi_m$ is inversely proportional to the absolute temperature $T$,i.e.,$\chi_m \propto \frac{1}{T}$.Given:$\chi_{m_1} = 1.0 	imes 10^{-5}$$T_1 = 27^{\circ} C = 27 + 273 = 300 \ K$$\chi_{m_2} = 1.5 	imes 10^{-5}$Using the relation $\frac{\chi_{m_1}}{\chi_{m_2}} = \frac{T_2}{T_1}$:$\frac{1.0 	imes 10^{-5}}{1.5 	imes 10^{-5}} = \frac{T_2}{300}$$\frac{1}{1.5} = \frac{T_2}{300}$$T_2 = \frac{300}{1.5} = 200 \ K$Converting back to Celsius: $T_2(^{\circ} C) = 200 - 273 = -73^{\circ} C$.

The magnetic susceptibility of a paramagnetic material is $1.0 \times 10^{-5}$ at $27^{\circ} C$ temperature. Then at what temperature its magnetic susceptibility would be $1.5 \times 10^{-5}$ (in $^{\circ} C$)?

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