The magnitude of magnetic moment (spin only) | vedclass

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(A) In $[NiCl_4]^{2-}$,the oxidation state of $Ni$ is $+2$.The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.Since $Cl^-$ is a weak field ligan

Vedclass · Accepted Answer

$2.82$

Vedclass · Answer

(A) In $[NiCl_4]^{2-}$,the oxidation state of $Ni$ is $+2$.The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.Since $Cl^-$ is a weak field ligand,it does not cause pairing of electrons in the $3d$ orbitals.Thus,there are $2$ unpaired electrons in the $3d$ subshell.The magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.For $n = 2$,$\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.82 \ B.M.$

$A$. Tetrahedral $NiCl_2Br_2^{2-}$	$B$. Square planar $Pt(NH_3)_2Cl_2$
$C$. Octahedral $Co(NH_3)_3Cl_3$	$D$. Square planar $Pd(NH_3)_3Br^{+}$
$E$. Octahedral $Co(en)_3^{3+}$

The magnitude of magnetic moment (spin only) of $[NiCl_4]^{2-}$ will be ........ $B.M.$

Similar Questions

The magnetic moment of $Fe^{2+}$ is $B.M$.

Out of the following two coordination entities,which is chiral (optically active)?
$(a)$ $cis-[CrCl_{2}(ox)_{2}]^{3-}$
$(b)$ $trans-[CrCl_{2}(ox)_{2}]^{3-}$

Indicate the complex or complex ion which does not show any geometrical isomerism:

Which of the following complex ions will have a magnetic moment of $2.82 \ BM$?

Which of the following molecules/ions can exhibit isomerism:
$A$. Tetrahedral $NiCl_2Br_2^{2-}$ $B$. Square planar $Pt(NH_3)_2Cl_2$
$C$. Octahedral $Co(NH_3)_3Cl_3$ $D$. Square planar $Pd(NH_3)_3Br^{+}$
$E$. Octahedral $Co(en)_3^{3+}$

Here,$en = 1,2-\text{diaminoethane}$.

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