The magnitudes of vectors overrightarrow{A},o | vedclass

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(C) Given that the magnitudes are $|\overrightarrow{A}| = 12$,$|\overrightarrow{B}| = 5$,and $|\overrightarrow{C}| = 13$.Since $\overrightarrow{A} + \

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$\pi / 2$

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(C) Given that the magnitudes are $|\overrightarrow{A}| = 12$,$|\overrightarrow{B}| = 5$,and $|\overrightarrow{C}| = 13$.Since $\overrightarrow{A} + \overrightarrow{B} = \overrightarrow{C}$,we can check if the magnitudes satisfy the Pythagorean theorem: $|\overrightarrow{A}|^2 + |\overrightarrow{B}|^2 = 12^2 + 5^2 = 144 + 25 = 169 = 13^2 = |\overrightarrow{C}|^2$.Since $|\overrightarrow{A}|^2 + |\overrightarrow{B}|^2 = |\overrightarrow{C}|^2$,the vectors $\overrightarrow{A}$ and $\overrightarrow{B}$ must be perpendicular to each other.Therefore,the angle between $\overrightarrow{A}$ and $\overrightarrow{B}$ is $\pi / 2$ radians (or $90^{\circ}$).

The magnitudes of vectors $\overrightarrow{A}$,$\overrightarrow{B}$,and $\overrightarrow{C}$ are $12$,$5$,and $13$ units respectively,and $\overrightarrow{A} + \overrightarrow{B} = \overrightarrow{C}$. Then the angle between $\overrightarrow{A}$ and $\overrightarrow{B}$ is:

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