The major product $'P'$ formed in this reaction is:

If the general formula of oxime and semicarbazone is $C=N-Z$,what is '$Z$' in oxime $(I)$ and semicarbazone $(II)$?

End products of the following sequence of reactions are:

Given below are two statements:
Statement $I$: $H_2N-CO-CH_2-CH_2-CO-CH_3$ under Clemmensen reduction conditions will give $HOOC-(CH_2)_3-CH_3$.
Statement $II$: $CH_3-CH(CH_3)-CH_2-CH(Cl)-CO-CH_3$ under Wolff-Kishner reduction conditions will give $CH_3-CH(CH_3)-CH_2-CH(Cl)-CH_2-CH_3$.
In the light of the above statements,choose the correct answer from the options given below:

Match the reactions given in column-$I$ with the suitable reagents given in column-$II$.

Column-$I$ (Reactions)	Column-$II$ (Reagents)
$(i)$. Benzophenone $\rightarrow$ Diphenylmethane	$(a)$. $LiAlH_4$
$(ii)$. Benzaldehyde $\rightarrow$ $1-$Phenylethanol	$(b)$. $DIBAL-H$
$(iii)$. Cyclohexanone $\rightarrow$ Cyclohexanol	$(c)$. $Zn(Hg) / \text{Conc. } HCl$
$(iv)$. Phenyl benzoate $\rightarrow$ Benzaldehyde	$(d)$. $CH_3MgBr, H_2O$

$A$ reaction of benzonitrile with one equivalent of $CH_{3}MgBr$ followed by hydrolysis produces a yellow liquid $P$. The compound $P$ will give a positive result for which of the following tests?