The major product (P) of the given reaction i | vedclass

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(C) The reaction proceeds via an acid-catalyzed dehydration of a secondary alcohol. $1$. Protonation of the $-OH$ group occurs to form a good leaving

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$1,2,5-$trimethylcyclohex$-1-$ene

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(C) The reaction proceeds via an acid-catalyzed dehydration of a secondary alcohol. $1$. Protonation of the $-OH$ group occurs to form a good leaving group $(-OH_2^+)$. $2$. Loss of a water molecule generates a secondary carbocation. $3$. $A$ $1,2$-methyl shift occurs to rearrange the secondary carbocation into a more stable tertiary carbocation. $4$. Finally,deprotonation (loss of $H^+$) from the adjacent carbon leads to the formation of the most stable,highly substituted alkene (Zaitsev product). Thus,the major product is $1,2,5$-trimethylcyclohex-$1$-ene.

Column-$I$ (Compound)	Column-$II$ (Major Product)
$A$. $1$-Methylcyclohexanol	$i$. $1$-Methylcyclohexene
$B$. Butan-$1$-ol	$ii$. But-$1$-ene
$C$. tert-Butyl alcohol	$iii$. Isobutylene
$D$. Butan-$2$-ol	$iv$. But-$2$-ene

The major product $(P)$ of the given reaction is .... (where,$Me$ is $-CH_3$)

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