The major product (P) in the reactionPh-CH=CH | vedclass

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(C) The reaction is an electrophilic addition of $HBr$ to the alkene $Ph-CH=CH-CH_2Br$.$1$. The proton $(H^+)$ from $HBr$ attacks the double bond to f

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$Ph-CH(Br)-CH_2-CH_2Br$

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(C) The reaction is an electrophilic addition of $HBr$ to the alkene $Ph-CH=CH-CH_2Br$.$1$. The proton $(H^+)$ from $HBr$ attacks the double bond to form the most stable carbocation.$2$. The carbocation formed at the benzylic position $(Ph-CH^+-CH_2-CH_2Br)$ is resonance-stabilized by the phenyl group.$3$. The bromide ion $(Br^-)$ then attacks this stable carbocation to form the major product.$4$. Thus,the major product is $Ph-CH(Br)-CH_2-CH_2Br$.

The major product $(P)$ in the reaction
$Ph-CH=CH-CH_2Br \xrightarrow{HBr} ?(P)$
$[$where $Ph$ is $-C_6H_5]$ is ....

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The major product $(P)$ in the reaction$Ph-CH=CH-CH_2Br \xrightarrow{HBr} ?(P)$$[$where $Ph$ is $-C_6H_5]$ is ....