The major product formed in the reaction is:

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(C) The reaction involves an $S_{N}2$ mechanism. The nucleophile $CN^{-}$ attacks the primary alkyl chloride carbon,which is the most reactive site fo

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$(iii)$

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(C) The reaction involves an $S_{N}2$ mechanism. The nucleophile $CN^{-}$ attacks the primary alkyl chloride carbon,which is the most reactive site for $S_{N}2$ substitution in the given molecule. The $Cl^{-}$ ion acts as the leaving group. The $Br$ atom attached to the $sp^{2}$ carbon of the alkene is not easily substituted under these conditions. Therefore,the $CN$ group replaces the $Cl$ atom,resulting in product $(iii)$.

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