The major product in the following reaction s | vedclass

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Question

(C) The reaction sequence is as follows:$1$. Toluene reacts with $Br_2$ in the presence of $UV$ light to undergo free-radical substitution at the benz

Vedclass · Accepted Answer

($2$-bromoethyl)benzene

Vedclass · Answer

(C) The reaction sequence is as follows:$1$. Toluene reacts with $Br_2$ in the presence of $UV$ light to undergo free-radical substitution at the benzylic position,forming benzyl bromide $(C_6H_5CH_2Br)$.$2$. Benzyl bromide reacts with $Mg$ in dry ether to form the Grignard reagent,benzylmagnesium bromide $(C_6H_5CH_2MgBr)$.$3$. The Grignard reagent reacts with formaldehyde $(CH_2O)$ followed by acidic hydrolysis $(H_3O^+)$ to form $2-$phenylethanol $(C_6H_5CH_2CH_2OH)$.$4$. Finally,$2$-phenylethanol reacts with $PBr_3$ to replace the hydroxyl group with a bromine atom,yielding ($2$-bromoethyl)benzene $(C_6H_5CH_2CH_2Br)$.

The major product in the following reaction sequence is:

Similar Questions

The synthesis of alkyl fluorides is best accomplished by

$C_2H_5Cl + AgF \longrightarrow C_2H_5F + AgCl$
The above reaction is called:

The best method for preparing alkyl chloride is:

$Cl_2$ reacts with $CS_2$ in the presence of an $I_2$ catalyst to form:

In the given reaction:
$CH_3-CH_2-COOH \xrightarrow[(ii) \ Br_2/\Delta]{(i) \ AgNO_3} [X]$
$[X]$ will be:

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