The major product in the given reaction is:

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(A) The reactant is $2$-bromobenzyl bromide. The reaction involves the nucleophilic substitution of the $-CH_2Br$ group with $NH_3$. The $-CH_2Br$ gro

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$2-$Bromobenzylamine

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(A) The reactant is $2$-bromobenzyl bromide. The reaction involves the nucleophilic substitution of the $-CH_2Br$ group with $NH_3$. The $-CH_2Br$ group is a benzylic halide,which is highly reactive towards nucleophilic substitution ($S_N2$ mechanism) due to the resonance stabilization of the transition state. In contrast,the $-Br$ atom directly attached to the benzene ring (aryl halide) is much less reactive towards nucleophilic substitution under these conditions due to the partial double bond character of the $C-Br$ bond and the instability of the phenyl cation. Therefore,the nucleophile $NH_3$ will selectively attack the benzylic carbon to form $2$-bromobenzylamine.

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