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(A) The reaction is an intramolecular Aldol condensation followed by dehydration. $1$. The base $NaOEt$ abstracts an $\alpha$-hydrogen from the methyl

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(A) The reaction is an intramolecular Aldol condensation followed by dehydration. $1$. The base $NaOEt$ abstracts an $\alpha$-hydrogen from the methylene group adjacent to the ester,forming an enolate. $2$. This enolate attacks the carbonyl carbon of the cyclopentanone ring,leading to the formation of a bicyclic $\beta$-hydroxy ester intermediate. $3$. Under heating $(\Delta)$,the intermediate undergoes dehydration (loss of $H_2O$) to form the stable conjugated $\alpha,\beta$-unsaturated ester. $4$. The structure formed is a bicyclo[$4.3$.$0$]nonane derivative with a double bond at the ring junction,which corresponds to option $A$.

The major product obtained in the following reaction is

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