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(A) In the presence of peroxides like benzoyl peroxide $((C_6H_5CO)_2O_2)$,the addition of $HBr$ to unsymmetrical alkenes follows the Anti-Markovnikov

Vedclass · Accepted Answer

$CH_3-CH(CH_3)-CH_2-CH_2-Br$

Vedclass · Answer

(A) In the presence of peroxides like benzoyl peroxide $((C_6H_5CO)_2O_2)$,the addition of $HBr$ to unsymmetrical alkenes follows the Anti-Markovnikov rule (also known as the peroxide effect or Kharasch effect). In this mechanism,the bromine radical attacks the less substituted carbon atom of the double bond to form a more stable radical intermediate. Reaction: $CH_3-CH(CH_3)-CH=CH_2 + HBr \xrightarrow{	ext{Peroxide}} CH_3-CH(CH_3)-CH_2-CH_2-Br$ ($1$-bromo$-3-$methylbutane).

The major product of the following chemical reaction is: $CH_3-CH(CH_3)-CH=CH_2 + HBr \xrightarrow{(C_6H_5CO)_2O_2} ?$

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