The major product of the following reaction is $CH_{2}=CH-CH_{2}-OH \xrightarrow[\text{Excess}]{HBr} \text{Product}$
- A$CH_{3}-CHBr-CH_{2}Br$
- B$CH_{2}=CH-CH_{2}Br$
- C$CH_{3}-CHBr-CH_{2}-OH$
- D$CH_{3}-CHOH-CH_{2}OH$
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