The major product of the following reaction i | vedclass

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(D) The reaction proceeds in two steps:$1$. The phenolic $-OH$ group reacts with $ClCH_2CH_2COCl$ to form an ester intermediate,$m-MeO-C_6H_4-O-CO-CH_

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(D) The reaction proceeds in two steps:$1$. The phenolic $-OH$ group reacts with $ClCH_2CH_2COCl$ to form an ester intermediate,$m-MeO-C_6H_4-O-CO-CH_2CH_2Cl$.$2$. In the presence of anhydrous $AlCl_3$,an intramolecular Friedel-Crafts acylation occurs. The acyl group attacks the ortho position relative to the $-OH$ group (which is now part of the ester linkage) to form a cyclic compound. The methoxy group $(-OMe)$ is an ortho-para directing group,and the cyclization occurs to form the most stable bicyclic structure,which is the coumarin derivative shown in option $D$.

The major product of the following reaction is:

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