The major product of the following reaction i | vedclass

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(A) $1$. The reaction proceeds via an $S_N2$ mechanism.$2$. In an $S_N2$ reaction, the nucleophile $(OH^-)$ attacks the electrophilic carbon from the

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(A) $1$. The reaction proceeds via an $S_N2$ mechanism.$2$. In an $S_N2$ reaction, the nucleophile $(OH^-)$ attacks the electrophilic carbon from the side opposite to the leaving group $(-Br)$.$3$. This results in a Walden inversion (inversion of configuration) at the chiral carbon atom bonded to the bromine.$4$. The $-NH_2$ group is not involved in this substitution reaction and remains in its original configuration.$5$. Therefore, the major product is the one where the $-OH$ group is attached with an inverted stereochemistry relative to the original $-Br$ position. Based on the provided options, option $(A)$ represents the product with the correct inverted configuration at the chiral center.

The major product of the following reaction is:
(Structure of $4$-bromo-pent-$2$-en-$2$-amine derivative) $\xrightarrow[{S_N2}]{{KOH}}$

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The major product of the following reaction is:(Structure of $4$-bromo-pent-$2$-en-$2$-amine derivative) $\xrightarrow[{S_N2}]{{KOH}}$