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(A) The reaction involves the dehydrohalogenation of a vicinal dibromide (or a dihaloalkane) using excess alcoholic $KOH$ at high temperature $(\Delta

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(A) The reaction involves the dehydrohalogenation of a vicinal dibromide (or a dihaloalkane) using excess alcoholic $KOH$ at high temperature $(\Delta)$.This is an $E_2$ elimination reaction that proceeds to form a conjugated diene.The starting material is $Ph-CH(CH_3)-CH(Br)-CH_2-CH_2-Br$.Upon treatment with excess alcoholic $KOH$,two molecules of $HBr$ are eliminated to form a conjugated system.The most stable product is the one with extended conjugation,which is $Ph-C(CH_3)=CH-CH=CH_2$ (or a similar conjugated diene structure as shown in option $A$).Thus,the major product is the conjugated diene.

The major product of the following reaction is:
$Ph-CH(CH_3)-CH(Br)-CH_2-CH_2-Br \xrightarrow{KOH \text{ (alc, excess)}, \Delta} ?$

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The major product of the following reaction is: $Ph-CH(CH_3)-CH(Br)-CH_2-CH_2-Br \xrightarrow{KOH \text{ (alc, excess)}, \Delta} ?$