The major product of the following reaction i | vedclass

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(A) The reaction proceeds in two steps:$1$. Markovnikov's addition of $HCl$ to the alkene: The $H^+$ adds to the terminal carbon of the double bond to

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(A) The reaction proceeds in two steps:$1$. Markovnikov's addition of $HCl$ to the alkene: The $H^+$ adds to the terminal carbon of the double bond to form a more stable secondary carbocation at the carbon adjacent to the benzene ring.$2$. Intramolecular Friedel-Crafts alkylation: The secondary carbocation formed acts as an electrophile and attacks the ortho position of the phenol ring (due to the activating $-OH$ group) to form a five-membered ring fused to the benzene ring. The final product is $4$-methyl-chroman derivative or specifically $2$-methyl$-2,3-$dihydrobenzofuran derivative depending on the chain length,but based on the structure provided,it forms a $2$-methyl$-2,3-$dihydrobenzofuran derivative.

The major product of the following reaction is:

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