The major product of the following reaction s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The $-OCH_3$ group is an electron-donating group and is ortho/para directing. In aromatic electrophilic substitution,the para position is favored

Vedclass · Accepted Answer

$4-$Ethylphenol

Vedclass · Answer

(A) The $-OCH_3$ group is an electron-donating group and is ortho/para directing. In aromatic electrophilic substitution,the para position is favored due to steric hindrance at the ortho position.Step-$1$: Friedel-Crafts Acylation of anisole with $CH_3COCl$ and anhydrous $AlCl_3$ yields $4$-methoxyacetophenone as the major product.Step-$2$: Clemmensen reduction of $4$-methoxyacetophenone using $Zn-Hg$ and concentrated $HCl$ reduces the acetyl group to an ethyl group,forming $4$-ethylanisole.Step-$3$: Cleavage of the ether linkage in $4$-ethylanisole with $HI$ yields $4$-ethylphenol and methyl iodide $(CH_3I)$.Thus,the major product is $4$-ethylphenol.

The major product of the following reaction sequence is:

Similar Questions

Which of the following ethers is formed from the reaction of an alcohol with diazomethane?

In the reaction $CH_3-CH(CH_3)-CH_2-O-CH_2-CH_3 + HI \xrightarrow{\text{Heated}} \dots$,which of the following compounds will be formed?

What product is formed when anisole reacts with concentrated $HNO_3$ and concentrated $H_2SO_4$?

Give $IUPAC$ names of the following ethers:
$(i)$ $C_2H_5OCH_2CH(CH_3)_2$
$(ii)$ $CH_3OCH_2CH_2Cl$
$(iii)$ $O_2NC_6H_4OCH_3(p)$
$(iv)$ $CH_3CH_2CH_2OCH_3$
$(v)$ $1$-Ethoxy-$4,4$-dimethylcyclohexane
$(vi)$ Ethoxybenzene

Anisole $\xrightarrow[\text{reflux}]{\text{excess } HI \text{ (conc.)}} \text{ Product}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module