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(B) The reaction is a hydroboration-oxidation of $2	ext{-methylbut-2-ene}$.Hydroboration-oxidation follows anti-Markovnikov addition of water ($H$ an

Vedclass · Accepted Answer

$3-$methylbutan$-2-$ol

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(B) The reaction is a hydroboration-oxidation of $2	ext{-methylbut-2-ene}$.Hydroboration-oxidation follows anti-Markovnikov addition of water ($H$ and $OH$) across the double bond.In $2	ext{-methylbut-2-ene}$ $(CH_3-C(CH_3)=CH-CH_3)$,the double bond is between $C_2$ and $C_3$.The $OH$ group attaches to the less substituted carbon atom $(C_3)$,and the $H$ atom attaches to the more substituted carbon atom $(C_2)$.This results in the formation of $3	ext{-methylbutan-2-ol}$ as the major product.

The major product of the following reaction sequence is:

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