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(C) The reaction of pent$-4-$en$-1-$ol with $Br_2$ in $H_2O$ proceeds via the formation of a cyclic bromonium ion intermediate.The internal hydroxyl g

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$(v)$ and $(vi)$

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(C) The reaction of pent$-4-$en$-1-$ol with $Br_2$ in $H_2O$ proceeds via the formation of a cyclic bromonium ion intermediate.The internal hydroxyl group $(-OH)$ then attacks the more substituted carbon of the bromonium ion in an intramolecular $S_N2$ fashion to form a five-membered tetrahydrofuran ring.Since the bromonium ion can form on either face of the double bond,the resulting product is a racemic mixture of the two enantiomers shown in $(v)$ and $(vi)$.

The major product of the reaction given below is

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