The major product of the reaction is CH_3-CH= | vedclass

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Question

(B) The reaction involves the addition of $HBr$ to the alkene group present in the molecule. The phenol group ($-OH$ attached to the benzene ring) doe

Vedclass · Accepted Answer

$CH_3-CH_2-CH(Br)-C_6H_4-OH$

Vedclass · Answer

(B) The reaction involves the addition of $HBr$ to the alkene group present in the molecule. The phenol group ($-OH$ attached to the benzene ring) does not undergo nucleophilic substitution reaction $(N.S.R.)$ with $HBr$ because the $C-OH$ bond has partial double bond character due to resonance. Therefore,the reaction is an electrophilic addition reaction $(E.A.R.)$ across the double bond. According to Markovnikov's rule,the $Br^-$ ion attaches to the more substituted carbon atom of the double bond. The reaction is: $CH_3-CH=CH-C_6H_4-OH + HBr \rightarrow CH_3-CH(Br)-CH_2-C_6H_4-OH$. Comparing this with the given options,the correct structure is represented by option $B$.

The major product of the reaction is $CH_3-CH=CH-C_6H_4-OH + HBr \rightarrow ?$

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