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Question

(A) The reaction involves the formation of a free radical intermediate $[A]$ followed by its addition to an alkene to form product $B$. $1$. In the fi

Vedclass · Accepted Answer

$A$ = $(CH_3)_2CH-\dot{C}(CN)CH_3$ and $B$ = $CH_3CH_2CH_2CH_2-C(CH_3)_2-CN$

Vedclass · Answer

(A) The reaction involves the formation of a free radical intermediate $[A]$ followed by its addition to an alkene to form product $B$. $1$. In the first step,the reaction of $2$-methylbutanenitrile with peroxide and heat leads to the abstraction of the hydrogen atom from the tertiary carbon,resulting in the most stable tertiary free radical: $(CH_3)_2C(\dot{C}HCN)CH_3$ or more simply $(CH_3)_2C(\dot{C}HCN)CH_3$ is not correct,the radical forms at the alpha position to the $CN$ group,which is $(CH_3)_2CH-\dot{C}(CN)CH_3$. $2$. In the second step,the radical $[A]$ adds to the terminal alkene $CH_3CH_2CH_2CH=CH_2$ (pent$-1-$ene). The radical adds to the terminal carbon to form a more stable secondary radical,which then abstracts a hydrogen atom or terminates to form the final product $B$. $3$. The structure of $B$ is $CH_3CH_2CH_2CH_2-C(CH_3)_2-CN$.

The major products $A$ and $B$ in the following reactions are:

Similar Questions

Among the given species,which carbocations are resonance stabilized?

Write structures of various carbocations that can be obtained from $2-$methylbutane. Arrange these carbocations in order of increasing stability.

The correct order of decreasing stability of the following carbocations is:
$I. CH_3-CH^{+}-CH_3$
$II. CH_3-CH^{+}-OCH_3$
$III. CH_3-CH^{+}-CH_2-OCH_3$

Rank the bond dissociation energies of the bonds indicated with the arrows (from smallest to largest).

The decreasing order of hydride affinity for the following carbocations is:
$A: CH_2=CH-C^+(CH_3)_2$
$B: (C_6H_5)_3C^+$
$C: (CH_3)_3C^+$
$D: (Cyclopropyl)_3C^+$
Choose the correct answer from the options given below:

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