The major products P and Q formed in the foll | vedclass

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(C) When $C_6H_5CN$ reacts with $Na / C_2H_5OH$,$C_6H_5CN$ undergoes reduction and the $-C \equiv N$ group changes to $-CH_2-NH_2$. Thus,the product $

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Benzylamine and Aniline

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(C) When $C_6H_5CN$ reacts with $Na / C_2H_5OH$,$C_6H_5CN$ undergoes reduction and the $-C \equiv N$ group changes to $-CH_2-NH_2$. Thus,the product $(P)$ is $C_6H_5CH_2NH_2$ (Benzylamine).The reaction occurs as follows:$C_6H_5CN + 4[H] \rightarrow C_6H_5CH_2NH_2$When $C_6H_5CN$ reacts with $(i)$ $HCl$ (conc. cold) and (ii) $Br_2 / KOH$,it follows the partial hydrolysis of nitrile to amide,followed by the Hoffmann-Bromamide degradation reaction. The final product $(Q)$ is aniline $(C_6H_5NH_2)$.The whole reaction is as follows:$C_6H_5CN$ $\xrightarrow{H_2O, OH^{-}} C_6H_5CONH_2$ $\xrightarrow{Br_2 / KOH} C_6H_5NH_2$Hence,option $(C)$ is the correct answer.

The major products $P$ and $Q$ formed in the following reactions of benzonitrile are

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