The major products P and Q formed in the foll | vedclass

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Question

(A) In reaction $(A)$,Friedel-Crafts alkylation of benzene with $n$-propyl chloride in the presence of $AlCl_3$ leads to the formation of a carbocatio

Vedclass · Accepted Answer

$P$ = Isopropylbenzene,$Q$ = Benzyl alcohol

Vedclass · Answer

(A) In reaction $(A)$,Friedel-Crafts alkylation of benzene with $n$-propyl chloride in the presence of $AlCl_3$ leads to the formation of a carbocation intermediate. The primary propyl carbocation rearranges to a more stable secondary isopropyl carbocation,which then attacks the benzene ring to form isopropylbenzene as the major product $P$.In reaction $(B)$:$(i)$ Friedel-Crafts alkylation of benzene with $CH_3Cl$ in the presence of $AlCl_3$ gives toluene.$(ii)$ Free radical halogenation of toluene with $Br_2$ in the presence of $hv$ (light) gives benzyl bromide $(C_6H_5CH_2Br)$.$(iii)$ Nucleophilic substitution of benzyl bromide with aqueous $KOH$ gives benzyl alcohol $(C_6H_5CH_2OH)$ as the major product $Q$.

The major products $P$ and $Q$ formed in the following reaction schemes are:

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