(A) The marked price of the bed is $Rs. 2400$.After the first discount of $10 \%$,the price becomes $2400 \times (1 - 0.10) = 2400 \times 0.9 = 2160$.

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(A) The marked price of the bed is $Rs. 2400$.After the first discount of $10 \%$,the price becomes $2400 \times (1 - 0.10) = 2400 \times 0.9 = 2160$.Let the second discount be $X \%$. The final price paid is $2160 \times (1 - \frac{X}{100}) = 1836$.Dividing both sides by $2160$,we get $(1 - \frac{X}{100}) = \frac{1836}{2160} = 0.85$.Therefore,$\frac{X}{100} = 1 - 0.85 = 0.15$.Thus,$X = 15 \%$.

Competitive Quantitative Aptitude Profit and Loss Profit and Loss

Medium

The marked price of a bed is $Rs. 2400$. The shopkeeper gives successive discounts of $10 \%$ and $X \%$ to the customer. If the customer pays $Rs. 1836$ for the bed,then find the value of $X$ in $\%$.

A
$15$
B
$18$
C
$12$
D
$10$

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Profit and Loss

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Profit and Loss

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The marked price of a bed is $Rs. 2400$. The shopkeeper gives successive discounts of $10 \%$ and $X \%$ to the customer. If the customer pays $Rs. 1836$ for the bed,then find the value of $X$ in $\%$.

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