The mass defect in a particular nuclear react | vedclass

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(D) Given mass defect, $\Delta m = 0.3 ~g = 0.3 	imes 10^{-3} ~kg = 3 	imes 10^{-4} ~kg$. Velocity of light, $c = 3 	imes 10^8 ~m/s$. The energy li

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$7.5 	imes 10^6$

Vedclass · Answer

(D) Given mass defect, $\Delta m = 0.3 ~g = 0.3 	imes 10^{-3} ~kg = 3 	imes 10^{-4} ~kg$. Velocity of light, $c = 3 	imes 10^8 ~m/s$. The energy liberated is given by Einstein's mass-energy equivalence formula, $E = \Delta m c^2$. $E = (3 	imes 10^{-4} ~kg) 	imes (3 	imes 10^8 ~m/s)^2$. $E = 3 	imes 10^{-4} 	imes 9 	imes 10^{16} ~J = 27 	imes 10^{12} ~J$. To convert Joules to kilowatt-hour $(kWh)$, we divide by $3.6 	imes 10^6 ~J/kWh$. $E = \frac{27 	imes 10^{12}}{3.6 	imes 10^6} ~kWh = 7.5 	imes 10^6 ~kWh$.

The mass defect in a particular nuclear reaction is $0.3 ~g$. The amount of energy liberated in kilowatt hour is: (Velocity of light $= 3 \times 10^8 ~m/s$)

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