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(D) The relationship between momentum $P$,mass $m$,and kinetic energy $E$ is given by the formula $P = \sqrt{2mE}$.Since the kinetic energies $E$ of b

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$2:3$

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(D) The relationship between momentum $P$,mass $m$,and kinetic energy $E$ is given by the formula $P = \sqrt{2mE}$.Since the kinetic energies $E$ of both substances are the same,we have $P \propto \sqrt{m}$.Therefore,the ratio of their momenta is $\frac{P_1}{P_2} = \sqrt{\frac{m_1}{m_2}}$.Given $m_1 = 4 	ext{ g}$ and $m_2 = 9 	ext{ g}$,we substitute these values:$\frac{P_1}{P_2} = \sqrt{\frac{4}{9}} = \frac{2}{3}$.Thus,the ratio of their momenta is $2:3$.

The masses of two substances are $4 \text{ g}$ and $9 \text{ g}$ respectively. If their kinetic energies are the same,then the ratio of their momenta will be

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