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(B) The maximum amplitude of an amplitude modulated wave is given by $A_{\max} = A_c + A_m = 12\, V$.The minimum amplitude of an amplitude modulated w

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$1$

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(B) The maximum amplitude of an amplitude modulated wave is given by $A_{\max} = A_c + A_m = 12\, V$.The minimum amplitude of an amplitude modulated wave is given by $A_{\min} = A_c - A_m = 3\, V$.Adding these two equations: $2A_c = 15 \Rightarrow A_c = 7.5\, V$.Subtracting the second from the first: $2A_m = 9 \Rightarrow A_m = 4.5\, V$.The modulation index $\mu$ is defined as $\mu = \frac{A_m}{A_c} = \frac{4.5}{7.5} = 0.6$.Given that the modulation index is $0.6\, x$,we have $0.6 = 0.6\, x$,which implies $x = 1$.

The maximum amplitude for an amplitude modulated wave is found to be $12\, V$ while the minimum amplitude is found to be $3\, V$. The modulation index is $0.6\, x$ where $x$ is $....$

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