The maximum efficiency of a full wave rectifi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The efficiency $(\eta)$ of a rectifier is defined as the ratio of the $DC$ output power to the $AC$ input power.For a full-wave rectifier,the $DC$

Vedclass · Accepted Answer

$\frac{8}{\pi^2} 	imes 100 \,\%$

Vedclass · Answer

(B) The efficiency $(\eta)$ of a rectifier is defined as the ratio of the $DC$ output power to the $AC$ input power.For a full-wave rectifier,the $DC$ output power is $P_{dc} = I_{dc}^2 R_L = (\frac{2I_m}{\pi})^2 R_L = \frac{4I_m^2 R_L}{\pi^2}$.The $AC$ input power is $P_{ac} = I_{rms}^2 (R_f + R_L) = (\frac{I_m}{\sqrt{2}})^2 (R_f + R_L) = \frac{I_m^2}{2} (R_f + R_L)$.Assuming the diode resistance $R_f$ is negligible compared to the load resistance $R_L$,the efficiency is $\eta = \frac{P_{dc}}{P_{ac}} = \frac{4I_m^2 R_L / \pi^2}{I_m^2 R_L / 2} = \frac{8}{\pi^2}$.Converting this to a percentage,the maximum efficiency is $\frac{8}{\pi^2} 	imes 100 \% \approx 81.2 \%$.

The maximum efficiency of a full wave rectifier is .........

Similar Questions

In the circuit shown below, the voltage appearing across the diode $D$ will be of the form:

$A$ $p-n$ junction diode as a rectifier converts

The output sinusoidal current versus time curve of a rectifier is shown in the figure. The average value of output current in this case is

$A$ sinusoidal voltage of peak value $200 \ V$ is connected to a diode and resistor $R$ in the circuit shown so that half-wave rectification occurs. If the forward resistance of the diode is negligible compared to $R$,the rms voltage (in volt) across $R$ is approximately:

$A$ full-wave rectifier supplies a load of $1 \ k\Omega$. The $a.c.$ voltage applied to the diode is $220 \ V_{rms}$. If the diode resistance is neglected,the value of the ripple voltage $(rms)$ is .... $V$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module