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(C) The maximum height $H$ of a projectile is given by $H = \frac{u^2 \sin^2 	heta}{2g}$.Since the angle of projection $	heta$ and gravity $g$ are c

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$10$

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(C) The maximum height $H$ of a projectile is given by $H = \frac{u^2 \sin^2 	heta}{2g}$.Since the angle of projection $	heta$ and gravity $g$ are constant,$H \propto u^2$.If $H$ increases by $10\,\%$,then $H' = 1.10 H$.Since $H' / H = (u' / u)^2$,we have $(u' / u)^2 = 1.10$,which implies $u' / u = \sqrt{1.10} \approx 1.0488$.The horizontal range $R$ is given by $R = \frac{u^2 \sin 2	heta}{g}$.Since $	heta$ and $g$ are constant,$R \propto u^2$.Therefore,the percentage increase in range is the same as the percentage increase in $H$,which is $10\,\%$.

The maximum height attained by a projectile is increased by $10\,\%$ by increasing its speed of projection,without changing the angle of projection. The percentage increase in the horizontal range will be $...........\,\%$

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