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The probability of finding an electron in the $p_x$ orbital is

Which of the following orbitals has the least energy?

Total number of electrons in $Cu$ atom having $m_l = 0$.

Considering the ground state of $Cr$ atom $(Z = 24)$,the number of electrons associated with azimuthal quantum numbers $l = 1$ and $l = 2$ are,respectively:

If the given four electronic configurations:
$(i)$ $n=4, l=1$
$(ii)$ $n=4, l=0$
$(iii)$ $n=3, l=2$
$(iv)$ $n=3, l=1$
are arranged in order of increasing energy, then the order will be:

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