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(C) For a shell with principal quantum number $n$,the total number of orbitals is $n^2$.For $n=3$,the total number of orbitals is $3^2 = 9$.Each orbit

Vedclass · Accepted Answer

$9$

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(C) For a shell with principal quantum number $n$,the total number of orbitals is $n^2$.For $n=3$,the total number of orbitals is $3^2 = 9$.Each orbital can hold a maximum of $2$ electrons,one with $m_s = +1/2$ and one with $m_s = -1/2$.Therefore,for $n=3$,there are $9$ orbitals,and each can accommodate exactly one electron with $m_s = -1/2$.Thus,the maximum number of electrons with $n=3$ and $m_s = -1/2$ is $9$.

The maximum number of electrons that can have principal quantum number,$n=3$,and spin quantum number,$m_s=-1/2$,is

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