The maximum number of electrons that can have | vedclass

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(B) For a given principal quantum number $n=4$,the possible subshells are $4s$,$4p$,$4d$,and $4f$. Each subshell contains at least one orbital with $m

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) For a given principal quantum number $n=4$,the possible subshells are $4s$,$4p$,$4d$,and $4f$. Each subshell contains at least one orbital with $m_l=0$ (specifically the $ns$,$np_z$,$nd_{z^2}$,and $nf_{z^3}$ orbitals). There are $4$ such orbitals in the $n=4$ shell that have $m_l=0$. Since each orbital can hold only one electron with a specific spin $m_s=\frac{1}{2}$,the total number of electrons is $4 	imes 1 = 4$.

The maximum number of electrons that can have the set of quantum numbers $n=4$,$m_l=0$,and $m_s=\frac{1}{2}$ is

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