The mean deviation about the mean for the fol | vedclass

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(C) First,we find the midpoints $(x_i)$ of each class interval and calculate the mean $(\bar{x})$:						Class Interval			Frequency $(f_i)$			Midpoint

Vedclass · Accepted Answer

$3.2$

Vedclass · Answer

(C) First,we find the midpoints $(x_i)$ of each class interval and calculate the mean $(\bar{x})$:						Class Interval			Frequency $(f_i)$			Midpoint $(x_i)$			$f_i x_i$			$|x_i - \bar{x}|$			$f_i |x_i - \bar{x}|$							$0-4$			$4$			$2$			$8$			$|2-6|=4$			$16$							$4-8$			$3$			$6$			$18$			$|6-6|=0$			$0$							$8-12$			$2$			$10$			$20$			$|10-6|=4$			$8$							$12-16$			$1$			$14$			$14$			$|14-6|=8$			$8$							Total			$N=10$			-			$\sum f_i x_i = 60$			-			$\sum f_i |x_i - \bar{x}| = 32$			Mean $(\bar{x})$ = $\frac{\sum f_i x_i}{N} = \frac{60}{10} = 6$Mean Deviation about the mean = $\frac{\sum f_i |x_i - \bar{x}|}{N} = \frac{32}{10} = 3.2$

$x_i$	$3$	$6$	$9$	$12$	$13$	$15$	$21$	$22$
$f_i$	$3$	$4$	$5$	$2$	$4$	$5$	$4$	$3$

The mean deviation about the mean for the following data is

Class Interval $0-4$ $4-8$ $8-12$ $12-16$

Frequency $4$ $3$ $2$ $1$

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The mean deviation about the mean for the following data is Class Interval $0-4$ $4-8$ $8-12$ $12-16$ Frequency $4$ $3$ $2$ $1$