The mean deviation from the mean for the data | vedclass

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(D) Step $ 1 $: Calculate the mean $ \bar{x} $ of the given data. $ \bar{x} = \frac{3 + 10 + 10 + 4 + 7 + 10 + 5}{7} = \frac{49}{7} = 7 $. Step $ 2 $:

Vedclass · Accepted Answer

$ 2.57 $

Vedclass · Answer

(D) Step $ 1 $: Calculate the mean $ \bar{x} $ of the given data. $ \bar{x} = \frac{3 + 10 + 10 + 4 + 7 + 10 + 5}{7} = \frac{49}{7} = 7 $. Step $ 2 $: Calculate the absolute deviations from the mean $ |x_i - \bar{x}| $. $ |3 - 7| = 4 $ $ |10 - 7| = 3 $ $ |10 - 7| = 3 $ $ |4 - 7| = 3 $ $ |7 - 7| = 0 $ $ |10 - 7| = 3 $ $ |5 - 7| = 2 $ Step $ 3 $: Calculate the mean of these absolute deviations. $ 	ext{Mean Deviation} = \frac{4 + 3 + 3 + 3 + 0 + 3 + 2}{7} = \frac{18}{7} \approx 2.57 $.

$x_i$	$5, 15, 25, 35, 45$
$f_i$	$8, 48, 56, 32, 16$

Class Interval	$0-2$	$2-4$	$4-6$	$6-8$	$8-10$
Frequency	$1$	$2$	$3$	$2$	$1$

Height in $cm$	Number of boys
$95-105$	$9$
$105-115$	$13$
$115-125$	$26$
$125-135$	$30$
$135-145$	$12$
$145-155$	$10$

$x_i$	$5$	$7$	$9$	$10$	$12$	$15$
$f_i$	$8$	$6$	$2$	$2$	$2$	$6$

The mean deviation from the mean for the data $ 3, 10, 10, 4, 7, 10, 5 $ is:

Similar Questions

The mean deviation about the median of the numbers $3x, 6x, 9x, \ldots, 81x$ is $91$. Then $|x| = $

The mean deviation of the following data about its mean is
$x_i$ $5, 15, 25, 35, 45$
$f_i$ $8, 48, 56, 32, 16$

The approximate value of the mean deviation about the mean for the following data is
Class Interval $0-2$ $2-4$ $4-6$ $6-8$ $8-10$
Frequency $1$ $2$ $3$ $2$ $1$

Find the mean deviation about the mean for the following data:
Height in $cm$ Number of boys
$95-105$ $9$
$105-115$ $13$
$115-125$ $26$
$125-135$ $30$
$135-145$ $12$
$145-155$ $10$

The mean deviation about the mean for the data:

$x_i$ $5$ $7$ $9$ $10$ $12$ $15$

$f_i$ $8$ $6$ $2$ $2$ $2$ $6$

is equal to: (in /$13$)

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